Question

A projectile is launched from level ground
with a velocity of 40 m/s at an angle of 30 from the ground What will be the vertical
component of the projectile's velocity just
before it strikes the ground?
(sin 30°= 0.5, cos 30 =0.87)
A)10 m/s B)20 m/s
C)30 m/s D)35 m/s
E)40 m/s
Answer with Solution plz​

Answer 1

Answer:

vertical component is 20 m/s

40 sin 30= 40×0.5

Answer 2

Answer:

vertical component

Explanation:

vertical component V sin theta V is equal to 40 sin theta is equal to 30 degree sin 30 equal to 1 by 2 where ans=(40×1/2 = 20) metre per second