Physics, asked by Zubairgul4688, 11 months ago

A projectile is launched vertically upwards, from earth's surface with speed equal to half of the escape sped upon earth's surface. The maximum height attained is (earth's radius):

Answers

Answered by AnmolRaii
0

an object, such as a bullet, that is fired from a gun or other weapon

बंदूक़ या किसी हथियार से दाग़ी गई गोली आदि कोई वस्‍तु

2.

any object that is thrown as a weapon

प्रक्षिप्‍त किया जाने वाला अस्‍त्र; प्रक्षेपास्‍त्र

Answered by rithvik301
0

Answer:

Explanation:

If v_{e}v  

e

​  

 is the escape velocity then

\dfrac{1}{2}v_{e}^2=\dfrac{GMm}{R}  

2

1

​  

v  

e

2

​  

=  

R

GMm

​  

 

Now the projectile is fired with speed kv_{e}kv  

e

​  

.

Then loss in kinetic energy is gain in potential energy

\implies \dfrac{1}{2}m(kv_{e})^2=GMm(\dfrac{1}{R}-\dfrac{1}{h})⟹  

2

1

​  

m(kv  

e

​  

)  

2

=GMm(  

R

1

​  

−  

h

1

​  

)

\implies k^2(\dfrac{GMm}{R})=GMm(\dfrac{1}{R}-\dfrac{1}{h})⟹k  

2

(  

R

GMm

​  

)=GMm(  

R

1

​  

−  

h

1

​  

)

\implies h=\dfrac{R}{1-k^2}⟹h=  

1−k  

2

 

R

​  

.

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