Question

A projectile is launched with an initial velocity of 40 m/s, at an angle of 30o above the horizontal. What si the maximum height reached by the projectile?

Answer 1

Question :-

A projectile is launched with an initial velocity of 40 m/s, at an angle of 30° above the horizontal. What is the maximum height reached by the projectile ? [take g = 10 m/s²]

Answer :-

Given -

• initial velocity , u = 40 m/s

• angle of projection , ⊖ = 30°

To Find -

maximum height reached

= ( u² sin²⊖ ) / 2g

= ( 40² sin²30° ) / 2(10)

= [ (40)² × (1/2)² ] / 20

= ( 1600 × 1/4 ) / 20

= 400 / 20

= 20 metres

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Hence, the maximum height reached by the projectile will be 20 metres.

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.... Thank You !!!!

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