Question

a projectile is projected at 10m/s by making an angle 60 degree to the horizontal .after sometimes its velocity makes at an angle of 30 degree to the horizontal.its speed at this instant is

Answer 1

Hey mate,

◆ Answer - 5.77 m/s

◆ Explaination-
# Given-
u = 10 m/s
θ = 60 °
θ' = 30 °
v = ?

# Solution-
When particle moves in projectile motion, its velocity has two components - vertical component and horizontal component.

At θ = 60 °,
Horizontal velocity = ucosθ

At θ' = 30°
Horizontal velocity = vcosθ'

During motion its horizontal component remains constant-
ucosθ = vcosθ'
10cos60 = vcos30
10 × 1/2 = v × √3/2
v = 10/√3
v = 5.77 m/s

Velocity of the projectile is at 30° is 5.77 m/s.

Hope that is helpful...

Answer 2

↑ is correct !!!!!!!!!!!!!