A projectile is projected at an angle alpha (>45 degree) with an initial velocity u. At what time is horizontal velocity will be equal to its vertical velocity?
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vx = u cos α
vy = u sin α - g t
vy = vx => t = u (sin α - cos α)/g = √2 (u/g) Sin (α - 45°)
vy = u sin α - g t
vy = vx => t = u (sin α - cos α)/g = √2 (u/g) Sin (α - 45°)
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