A projectile is projected at an angle of 45 degree to horizontal. If H is the
maximum height and R is horizontal range, then relation between H and R is
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Answered by
65
Maximum height, H = (u²sin²θ)/2g
Given the angle of projection is 45°,
∴ H= [u²(1/√2)²]/2g= u²/4g = 1/4 (u²/g)---(1)
Range , R = (u²sin2θ)/g
∴R = (u²sin90°)/g = u²/g
Hence, (1)⇒ H = R/4
Given the angle of projection is 45°,
∴ H= [u²(1/√2)²]/2g= u²/4g = 1/4 (u²/g)---(1)
Range , R = (u²sin2θ)/g
∴R = (u²sin90°)/g = u²/g
Hence, (1)⇒ H = R/4
Answered by
11
Answer:R=4H is the required answer
Explanation:
Plz check the attachment.
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