Question

a projectile is projected at angle 45 degree with velocity 9.8 metre per second its horizontal range is ?? (g =10)​

Answer 1

Given,

θ = 45°

u = 9.8 m s^(-1)

We know that, horizontal range,

R = u² sin(2θ) / g

R = 9.8² sin(2 × 45°) / 10

R = 9.604 sin 90°

R = 9.604 m