Question

A projectile is projected at angle of

600 with horizontal with a velocity

of 20ms-1

. The velocity of

projectile at maximum height is ?​

Answer 1

Answer:

$\large\mathbb{\underbrace\purple{ANSWER}}$

Velocity at max height =20cos60

=10 m/s.

i.e.,

using momentum conservation

10×2m=m×v

⇒v=20 m/s.

MARK AS BRAINLIEST

Answer 2

Answer:

zero

Explanation:

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