Physics, asked by Rudra788, 1 month ago

A projectile is projected from origin having vertical as y-axis. The position of particle is given by x = 6t and y = 8t - 5t2 where x and y are in meter. If angle of projection in degree to nearest integer is (k + 50), then find k​

Answers

Answered by amitnrw
2

Given : A projectile is projected from origin having vertical as y-axis. The position of particle is given by x = 6t and y = 8t - 5t² where x and y are in meter.  

angle of projection in degree to nearest integer is (k + 50),

To find :  k

Solution:

y = 8t - 5t²

dy/dt = 8 - 10t

x = 6t

dx/dt  = 6

dy/dx  = (8 - 10t)/6  = (4 - 5t)/3

at t = 0  , x = 0 , y = 0

dy/dx = 4/3

tanα = 4/3

=> α = 53.13° ≈ 53°

Hence,

 k + 50 =  53

=> k = 3

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