Question

A projectile is projected from the ground by making an angle 60 degrees with the horizontal .After one second projectile makes an angle of 30 degrees with horizontal the maximum height attained by projectile is??

Answer 1

Answer:

v=v

x

i

^

+v

y

j

^

v=i×u

x

cosθ

i

^

+u

x

×cosθ×tan(θ/2)

j

^

v

2

=u

2

cos

2

θ+u

2

cos

2

θ×tan

2

θ/2

v

2

=u

2

cos

2

θ(1+tan

2

θ/2)

v

2

=u

2

cos

2

θ×sec

2

θ/2

∴ Radius of curvature =

gcosθ/2

u

2

cos

2

θ×sec

2

θ/2

=

4×3×10×

3

400×1×4×2

3

3

80

Explanation:

hope it helps you bro have a great day