Question

A projectile is projected from xy plane with velocity v=3i+4j+5k

Answer 1

Answer:

5 metre per second

Explanation:

xy plane=z plane

so in z axis there is 5 unit

Answer 2

Answer:

A projectile is projected.

Explanation:

Given:

$v= 3i+4j+5k$

Calculation:

As we know that:

$cos$θ=$\frac{Base}{Hypotenuse}$

$cos$θ=$\frac{5}{5\sqrt{2} }$

     =$\frac{1}{\sqrt{2} }$

θ=$45$°

$v=\sqrt{3^{2}+4^{2} +5^{2} }$

$v=\sqrt{9+16+25} \\ =5\sqrt{2}$

Range =

               $\frac{50sin(2(45))}{10} \\\frac{50}{10} \\5$

Hence , Range of projection is $5m$