A projectile is projected horizontally from the top of cliff of height 80 m with a velocity 21.5 m/s. How long will it take to reach the bottom? (g=10m/s2) CORRECT ANSWER ONLY GET BRAINLIEST
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Answered by
1
Answer: 4 seconds
Explanation: Displacement in y direction (Sy) = 80m
Acceleration in y direction (Ay) = 10 m/s2
Initial Velocity in y direction = zero
Sy = Uy*t + 1/2*a*t2
80 = 0 + 5*t2
16 = t2
4 = t
Answered by
2
Answer:
We have given displacement in y direction as 80 metres
Acceleration in y direction = 10 m/s²
Velocity = 0 in y
80= 1/2 * 10*t²
t=+4 or -4
as time is always positive hence
time is 4 seconds
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