Question

A projectile is projected in a plane from origin with intial velocity u vector=u1i+u2j. If acceleration due to gravity is taken along -j, then maximum displacement in x- direction would be
1) 2u1u2/g 2) u1^2/g
3) 4u1u2/g 3) u2^2/g

Answer 1

as we know ,
if a projectile projected with speed u and inclination with horizontal is ∅ then,
initial velocity vector (u) = ucos∅i + usin∅j ----(1)
and displacement in x-direction { horizontal range } = 2(usin∅)(ucos∅)/g ---------(2)

a/c to question,
initial velocity vector = u1i + u2j -------(3)
compare the equations (1) and (3)
u1 = ucos∅
u2 = usin∅
now , put this in equation (2)

so, displacement in x-direction = 2(u1)(u2)/g

hence, option (1) is correct.

Answer 2

Answer:option 1

Explanation:

Plz check the attachment.