Question

a projectile is projected in x y plane under the effect of gravity with speed u at an angle 60 with horizontal if p is the initial momentum of the projectile then find its momentum at the highest point​

Answer 1

Answer:

The total time of flight is

 Resultant displacement is zero in Vertical direction.

Therefore, by using equation of motion

  s=ut−21gt2

 gt=2sinθ

 t=g2sinθ

(b). The  horizontal range is

Horizontal range OA = horizontal component of velocity × total flight time

  R=ucosθ×g2usinθ

 R=gu2sin2θ

(c). The maximum height is

It is the highest point of the trajectory point A. When the ball is at point A, the vertical component of the velocity will be zero.

By using equation of motion

  v2=u2−2as

 0=u2sin2θ−2gH

 H=2gu2sin2θ

Hence, this is the required solution

Explanation:

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