Question

A projectile is projected so that it attains maximum height of 25m. What is the maximum range of Projectile.
(a) 100m
(b) 80m
(c) 50m
(d) 25m. ​

Answer 1

Answer:

Explanation:

maximum height can be attained only when the projectile is launched at 90°

threrfore ,

h= u^2/2g

25×2×9.8= u^2

490=u^2

7√10=u

then for range ,

the maximum range occurs at 45°

R = u^2/g

R = 490/9.8

R = 50 m

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