A projectile is projected with a speed 30m/s at an angle 30 with the vertical the speed of the projectile when its direction of motion makes an angle 30 with horizontal is
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projectile makes an angle 30° with vertical it means , it also makes 60° angle with horizontal.
Let speed of projectile at that position where it makes 30° angle with horizontal.
we know, horizontal component of projectile doesn't change.
so, initial horizontal component of projectile = final horizontal component of projectile
or, ucos60° = vcos30°
or, 30cos60° = vcos30° [ given, u = 30m/s ]
or, 30 × 1/2 = v × √3/2
or, v = 10√3 m/s
hence, answer is 10√3 m/s
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A projectile is projected with a speed 30m/s at an angle 30 with the vertical the speed of the projectile when its direction of motion makes an angle 30 with horizontal is
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