Question

A projectile is projected with initial speed 10 metre per second at an angle 37 degree with the horizontal .the speed of projectile at its maximum height will be
a)10m/s
b)4m/s
c)6m/s
d)8m/s​

Answer 1

Explanation:

first find the hmax

hmax= u²sin²@/2g

=45/20

=2.25m

at hmax it's velocity in y component

becomes zero

and it will only have it's velocity of x component that is ucos37

= 10×4/5

=8m/s