A projectile is projected with initial velocity (6i+8j) m/s if g=10m/s the horizontal range
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Answer:9.6m
Explanation:along x direction velocity is ucos@ and along y direction it's usin@
Range = Usquare sin2@/g
Sin2@ = 2sin@cos@ (maths)
Formula modifies to 2usin@ucos@/g
Along x ucos@=6 and along y usin@=8
Range =2*6*8\10= 9.6m
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