Question

A projectile is projected with initial velocity
(6i+ 8j) m/s. If g = 10 m/s? then horizontal range
is:
(1) 4.8 metre
3) 19.2 metre
(2) 9.6 metre
(4 14.0 metre
​

Answer 1

Answer:

Explanation:

Solution,

Here, we have

Velocity of projection,  v = (6i + 8j) m/s

Acceleration due to gravity, g = 10 m/s²

Here, we have

vx = 6 m/s

vy = 8 m/s

We know that,

⇒ v² = vx² + vy²

⇒ v² = (6)² + (8)²

⇒ v² = 36 + 64

⇒ v² = 100

⇒ v = 10 m/s.

So, Here we get

SinΘ = 8/10 and,

CosΘ = 6/10

⇒ R = v²sin 2Θ/g

⇒ R = v²2 sinΘ cosΘ/g

⇒ R = 10 × 10 × 2 × 8/10 × 6/10 × 1/10

⇒ R = 2 × 6 × 8/10

⇒ R = 9.6 m.

Hence, the horizontal range of a projectile is 9.6 m.