A projectile is projected with kinetic energy K . If it has the maximum possible horizontal range, then kinetic energy at highest point will be?
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Answered by
12
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~* THE ANSWER OF YOUR QUESTION IS..*~
✍✍✍✍✍✍✍✍________________________________________
AT TOPMOST POINT
VELOCITY OF PROJECTILE IS
VCOS THETA.........(1)
ACCORDING TO QUESTION
GIVEN KINETIC ENERGY =K
K =1/2 mv^2
FROM THIS ..WE GET V = UNDERROOT OF 2K /M
PUTTING THIS VALUE IN EQUATION .(.1)
YOU WILL GET
KINETIC ENERGY = 1/2 X UNDERROOT OF 2K/M X 1/ ROOT 2
SOLVING THIS YOU WILL GET
KINETIC ENERGY= K/2
~* THE ANSWER OF YOUR QUESTION IS..*~
✍✍✍✍✍✍✍✍________________________________________
AT TOPMOST POINT
VELOCITY OF PROJECTILE IS
VCOS THETA.........(1)
ACCORDING TO QUESTION
GIVEN KINETIC ENERGY =K
K =1/2 mv^2
FROM THIS ..WE GET V = UNDERROOT OF 2K /M
PUTTING THIS VALUE IN EQUATION .(.1)
YOU WILL GET
KINETIC ENERGY = 1/2 X UNDERROOT OF 2K/M X 1/ ROOT 2
SOLVING THIS YOU WILL GET
KINETIC ENERGY= K/2
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Answered by
2
Answer:
k/2
Explanation:
1/2 mv^2134tdwfhi
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