Question

a projectile is projected with maximum with speed o 20m/sat an angle of 40degree to horizontal calculated
a.maximm height
2.time of flight
3. range of projectile​

Answer 1

Answer:

8.432 m

2.62 second

40.14 m

Explanation:

time of flight =20×sin40°/9.8 ×2=2.62 second

range of projectile =20 ×cos40°×2.62=40.14 m

maximum hight =400×(sin40°)^2/(2×9.8)= 8.432 m