Question

A projectile is projected with speed of 50m/s at an angle of 37° with the horizontal. Find its speed at highest point of its trajectory?​

Answer 1

Answer:

Explanation:

At the highest point, the stone has only horizontal velocity but not vertical velocity.

Initial horizontal velocity of stone (ux)= ucosθ=50×cos37=45 m/s

Since, there is no acceleration in the horizontal direction. so horizontal velocity of stone remains constant with time.

Thus, speed at the highest point  ( V x)=(ux)=45m/s  

Hope this was uselful

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