Question

A projectile is projected with velocity 40 m/s for maximum range. Calculate its time of flight. [Take g = 10 m/s2]

Answer 1

Velocity of projection = 40 m/s , and max range is expected.

So, angle of projection has to be 45° for max range.

Now, let time period be T :

$T = \dfrac{2u \sin( \theta) }{g}$

$\implies T = \dfrac{2 \times 40 \times \sin( {45}^{ \circ} ) }{10}$

$\implies T = 8 \times \dfrac{1}{ \sqrt{2} }$

$\implies T = 4 \sqrt{2} \: sec$

So, time of flight is 4√2 seconds.