Question

A projectile is projected with velocity u =a i +b j from ground if acceleration due to gravity is g, then the change in velocity of the projectile in t second of projection is​

Answer 1

Explanation:

\begin{lgathered]\vec[u]-a\ \vec[i] +b\ \vec{j}\\\\\frac{H}{R}=\frac{1}{4} Tan\theta=1/2\\\\sol Tan\theta-2,\\\\from\ \vec{u},\ Tan\theta=\frac{b}{a}\\\\Hence, \ b=2a\end{lgathered]

Fa

i

+b

H

4

1Tane=1/2

so Tane=2,

from

, Tane=

a

b

all 80% 1

Hence, b=2a