Question

A projectile is thrown at 45°, its range is 90 m what is its initial velocity A) 10 ms) C) 50 ms-1 B) 30 ms- D) 90 ms-1​

Answer 1

Answer:

B.30m/s

Explanation:

Hope it helps you.

Answer 2

The initial velocity is 30 m/s

Given,

A projectile is thrown at 45°

Range = 90 m

To Find,

Find the initial Velocity

Solution,

• Equations of motion are used to express how a physical system behaves in terms of its motion. The equations of motion are the relationships between different terms and quantities.
• There are primarily three equations of motion, commonly known as the laws of constant acceleration, in the situation of uniform acceleration.
• Any item will accelerate in the presence of forces. The speed of the object varies as a result of this acceleration.
• Therefore, the initial velocity is the object's velocity prior to the change brought on by acceleration. The velocity will be the final velocity when the item has been accelerating for a while.

so, we know that,

$R= \frac{u^{2}*sin2θ }{g}$

[ Where, R = Range,

u = initial Velocity

g = gravitational force]

$= > 90 = \frac{u^{2} * sin(2*45)}{10}$

$= > 90= \frac{u^{2}* sin90 }{10}$

$= > u^{2} = \frac{90*10}{1}$

$= > u^{2} = 900$

$= > u^{2} = \sqrt{900} = 30$

so, initial Velocity = 30 m/s

Hence, the initial Velocity is 30 m/s

#SPJ2

For more information about initial velocity, you can refer to the following questions

What us initial velocity

https://brainly.in/question/647263

how to find initial velocity

https://brainly.in/question/3850296