a projectile is thrown at an angle of 30 degree to the horizontal. what should be the range of initial velocity so that it's range will be between 40m and 50m? assume g= 10ms-2
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Answer:
21.5 ≤ u ≤ 24
Explanation:
Range = u²sin2∝/g = u²sin60/10 = √3u²/20
40≤ √3u²/20 ≤ 50
800/√3 ≤ u² ≤ 1000/√3
461.88 ≤ u² ≤ 577.35
461.88 ≤ u² ≤ 577.35
21.5 ≤ u ≤ 24
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