Question

A projectile is thrown at an angle of the 15 for same range what is the another angle ​

Answer 1

Explanation:

given

g

u

2

×sin

2

×15

∘

=1.5

g

u

2

×

2

1

=1.5

g

u

2

=3

R=

g

u

2

×sin

2

×45∘

=

g

u

2

×sin90∘=3km

Answer 2

Answer:

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