Physics, asked by naveenkumar94, 1 year ago

a projectile is thrown at an angle theta from the horizontal with velocity U under the gravitational field of Earth. Find the expression for time of flight and horizontal range.​

Answers

Answered by sehaj0001
22
Time of flight = time of ascent + time of descent
T = t + t
T=2t
=2 (u sinθ/g)
= 2u sinθ/g

horizontal range=uniform velocity along horizontal×Time of flight
R = u × t
=(u cosθ)×(2u sinθ/g)
=u^2/g (2 Sun θ cosθ)


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