a projectile is thrown at an angle theta from the horizontal with velocity U under the gravitational field of Earth. Find the expression for time of flight and horizontal range.
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Time of flight = time of ascent + time of descent
T = t + t
T=2t
=2 (u sinθ/g)
= 2u sinθ/g
horizontal range=uniform velocity along horizontal×Time of flight
R = u × t
=(u cosθ)×(2u sinθ/g)
=u^2/g (2 Sun θ cosθ)
if it helps u plz mark as brainliest
T = t + t
T=2t
=2 (u sinθ/g)
= 2u sinθ/g
horizontal range=uniform velocity along horizontal×Time of flight
R = u × t
=(u cosθ)×(2u sinθ/g)
=u^2/g (2 Sun θ cosθ)
if it helps u plz mark as brainliest
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