a projectile is thrown at angle b with vertical. it reaches a maximum height 10m. The time taken to reach the highest point of its path is
Anonymous:
please let me know if the answer is√2
???
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can it be solved by using √2H/g
sorry T = √2H/√g
nooo
its 2d motion so we have to use the formula
i got it.....thnx
grt answer
tq
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