Question

A projectile is thrown at angle of 30° with
horizontal with speed v. Minimum speed
of projectile during motion, is

Answer 1

Answer:

$\frac{\sqrt{3}v}{2}$

Explanation:

As speed of body is v we can write is as:

vcos∅i+vsin∅t-0.5gt²j

At Hmax , y component is 0.

Therefore Speed at Hmax is:

vcos∅i=As ∅=30

$\frac{\sqrt{3}v}{2}$

Thanks