Question

A projectile is thrown at angle ß with vertical. It reaches a maximum height H. The time taken to reach the highest point of its path is?​

Answer 1

Answer:

We have, H = (v2cos2β)/(2g)

Or, vcosβ = √(2gH)

And t = (vcosβ)/g

= √(2gH)/

= √(2gH)/g

Plz mark as brainiest