a projectile is thrown from a point 39.2 away from the food a building 19.6 m height and the just reach top horizontal find the velocity of projection and the angle of thown
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Answer:
98.5m/s
Explanation:
Given height h=19.6 m; θ=450
We know time=g2h=9.82×19.6=4=2
Also we know velocity =TimeDistancetravelled=219.6=9.8m/s
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