Question

A projectile is thrown from o on an inclined plane as shown and hits the plane perpendicularly​

Answer 1

Answer:

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Answer 2

Answer:

The range of projectile will be $70\sqrt{3}$ m

Explanation:

Given :-

u = $10\sqrt{7}$m/s

g = 10 m/s

β = 30°

we know the range of projectile is given by the formula:-

R = $\frac{u^{2}sin2 \beta }{g}$

R =$\frac{ (10\sqrt{7})^{2} sin2(30)}{10}$

R = $\frac{(10\sqrt{7})^{2} 2\sqrt{\frac{3}{2} } }{10}$

R = $\frac{700\sqrt{3} }{10}$

R = $70\sqrt{3}$m