Question

A projectile is thrown from the foot of inclined plane of inclination theta with the horizontal . Velocity of projectile is v =(24i^ +16j^ ) ms . Projectile strikes the inclined plane at right angle . take g = 10 ms2 . Find angle of inclination of plane with the horizontal.

Answer 1

 let after time t its inclination with horizontal is 45   at this time Vy /Vx =tan45  or Vy =Vx     Vx remains constant =147cos60 =Vy     now using equation of motion for verticle direction    Vy=Uy-gt..........eq1   Uy=147sin60 ,Uy=147cos60  putting in eq 1,     t=5.36 sec