A projectile is thrown horizontally with a speed of 20 ms⁻¹. If g is 10 ms⁻², then the speed of the projectile after 5 second will be nearly(a) 0.5 ms⁻¹(b) 5 ms⁻¹(c) 54 ms⁻¹(d) 500 ms⁻¹
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Vy = uy - gt ------------ (1)
here,
u = 0
g = 10
t = 5
(1) -----Vy = 0-10×5
Vy = -50
we have to find the speed
so , speed = √Vx^2 + Vy^2 ----------(2)
here ,
Vx = 20
Vy = 5
(2) --------- speed = √ 400 + 2500
= √2900
= 54 (approx)
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