A projectile is thrown in the upword direction making an angle of 60 with the horizontal direction with a velocity of 150 m/s.Then the time aftar which is inclination with the horizontal is 45 is
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I saw this question somewhere online but in that case the velocity is 147m/s and everything is same
So here is the answer
let after time t its inclination with horizontal is 45
at this time Vy /Vx =tan45 or Vy =Vx
Vx remains constant =147cos60 =Vy
now using equation of motion for verticle direction
Vy=Uy-gt..........eq1
Uy=147sin60 ,Uy=147cos60
putting in eq 1,
t=5.36 sec
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