Question

A projectile is thrown into space as to have the maximum possible horizontal range equal to 400m. Taking the point of projection as the origin, the coordinates of the point where the velocity of the projectile is minimum are

Answer 1

maximum range is obtained at 45^
x coordinate for minimum velocity will=400/2=200
at top velocity is minimum=v cos theta
height max=(v)square(sin)square theta/2g=(v)square/4g=1/4(range)=400/4=100
so y coordinate will be 100
coordinates of the point =200,100

Answer 2

Answer:

200 , is the right answer bro dude s have fun