Question

a projectile is thrown into space so as to have maximum possible range of 400 metre taking the point of projection as the origin the co-ordinate of the point where the velocity of the projectile is minimum is​

Answer 1

Answer:

(200, 100)

Explanation:

Range = (u²sin2∅)/g

Maximum range is possible when sin2∅ = 1

sin2∅ = sin90

2∅ = 90

∅ = 45 degrees

Therefore, angle of projection is 45 degrees

Also, maximum range can be written as

400 m = u²/g

Velocity of projectile is minimum at maximum height

H = (u²Sin²∅) / (2g)

= (u²/g) × (Sin²∅)/2

= 400 m × (Sin²45)/2

= 400 m × 1/4

= 100 m

Coordinates of the point where velocity is minimum is same as that of maximum height. At this point horizontal distance is half of range.

So, coordinates are: (x, y) = (200, 100)