Question

A projectile is thrown up with initial speed u making
angle with the horizontal. It reaches the
maximum height H. If maximum height is to be
doubled then initial speed of throw for same angle
is​

Answer 1

Answer:

if α = 90°, then the formula simplifies to: hmax = h + V₀² / (2 * g) and the time of flight is the longest. ...

if α = 45°, then the equation may be written as: ...

if α = 0°, then vertical velocity is equal to 0 (Vy = 0), and that's the case of horizontal projectile motion.

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