Question

a projectile is thrown with a speed of 10 m s -1 at 30* with horizontal.find the time of flight and maximum height it raised?​

Answer 1

Answer:

Explanation:

TIME = 2(10)sin30/10=10/10= 1sec

maximum height= u^2sin^2theta/2g=10^2sin^2(30)/20

=1.25 meters

Answer 2

Explanation:

45√3 chapter notes Sir John and his