Question

a projectile is thrown with a velocity 5metre per second at an angle of 30 degree with the horizontal. calculate the time of flight​

Answer 1

Answer:

Given,

u = 5m/s

Φ = 30°

if g = 10m/s

Time of flight = (2u sinΦ)/g

= (2*5*sin30°)/10

= (10*1/2)/10

= 1/2

= 0.5s

Answer 2

Given:

• Velocity of projection = 5 m/s
• Angle of projection = 30 °
• Acceleration due to gravity = 9.8 m/s²

To find:

• Time of flight

Solution:

Time of flight of the body is given by,

$\longrightarrow\sf{T = \dfrac{2u\sin\theta}{g}}$

here,

• T = time of flight
• u = velocity of projection
• θ = angle of projection
• g = acceleration due to gravity

Now let's substitute the values,

$\longrightarrow\sf{T = \dfrac{2\times 5 \times \sin30}{9.8}}$

$\longrightarrow\sf{T = \dfrac{2\times 5 \times 1 }{2 \times 9.8}}$

$\longrightarrow\sf{T = \dfrac{ 5 }{ 9.8}}$

$\longrightarrow\boxed{\sf{T = 0.51 s }}$

The time of flight of the projectile is 0.51 s.