Question

A projectile is thrown with a velocity of 10 ms⁻¹ at an angle of 30° with horizontal. The value of maximum height gained by it is *​

Answer 1

To Find :-

• The value of maximum height gained by it is.

Solution :-

Given,

• Angle ($\bold{\theta}$) = 30°
• Velocity (u) = 10 ms-¹
• Acceleration due to gravity (g) = 10 ms-²

The maximum height gained formula is given as ;

$\red \bigstar \sf \: h = \dfrac{u^2 sin^2\theta}{2g}$

[ Put the values ]

$\longrightarrow \sf \: h = \dfrac{10 {}^{2} \times sin {}^{2} 30 \degree }{2 \times 10}$

$\longrightarrow \sf \: h = \dfrac{100 \times ( \frac{1}{2}) {}^{2} }{20}$

$\longrightarrow \sf \: h = 5 \times \dfrac{1}{4}$

$\longrightarrow \sf \: h = 1.25 \: m \: \green \bigstar$

Therefore,

The value of maximum height gained by it is 1.25 m.