Physics, asked by bhavarannya2863, 10 months ago

A projectile is thrown with a velocity of 20m/s at an angle of 60° with the horizontal .after how much time the velocity vector will make an angle 45° with the horizontal.

Answers

Answered by azizalasha

2

Answer:

solved

Explanation:

tan45 = 1 = vy/vx

vy = vx

20sin60 - gt = 20 cos30

t = 20(sin60 - cos60)/10 = √3 - 1 sec.

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