A projectile is thrown with a velocity v0=3i+4j m/s where i and j are unit vectors
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Answer:
V= √(Vx2+Vy2)=√(3×3+4×4)=√25=5
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IT MEANS OVERALL VELOCITY INITIALLY WOULD BE SQRT(3^2+4^2)
=5 m/s
....ANS
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