Physics, asked by Delirimo03, 10 months ago

A projectile is thrown with an initial velocity of (vxi^+vyj^)m/s. If the range of the projectile is double the maximum height, then vy is

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Answers

Answered by shantanukumar9686
2

Answer:

v

=a

i

^

+b

j

^

vsinθ=b

vcosθ=a

R=

g

u

2

sin2θ

=

g

2∗usinθ∗ucosθ

=

g

2ab

H=

2g

u

2

sin

2

θ

=

2g

b

2

R=2H

g

2ab

=2

2g

b

2

b=2a

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