A projectile is thrown with an initial velocity of (vxi^+vyj^)m/s. If the range of the projectile is double the maximum height, then vy is
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Answer:
∵
v
=a
i
^
+b
j
^
vsinθ=b
vcosθ=a
R=
g
u
2
sin2θ
=
g
2∗usinθ∗ucosθ
=
g
2ab
H=
2g
u
2
sin
2
θ
=
2g
b
2
R=2H
g
2ab
=2
2g
b
2
b=2a
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