Question

A projectile is thrown with an initial velocity velocity of a vector is equal to a icap + b j cap projectile is maximum height reached by then

Answer 1

Answer:

V = a i + b j

b = dy/dt a = dx/dt

b/a = dy/dx = tan θ

Range = R = 2 H

Max Height = H

H/R = 1/4 * tan θ

So tan θ = 2

tan θ = b/a = 2 => b = 2 a