Question

A projectile is thrown with initial velocity u→=ai^+bj^ m/s. If the range is twice the maximum height then wht wil b the ans and how? Plz solve also.
A) b=a/2 or a or 2a or 4a..

Answer 1

$\vec{u}=a\ \vec{i}+b\ \vec{j}\\\\\frac{H}{R}=\frac{1}{4}Tan\theta=1/2\\\\so\ Tan\theta=2,\\\\from\ \vec{u},\ Tan\theta=\frac{b}{a}\\\\Hence, \ b=2a$

Answer 2

Answer:

Explanation:this what the answer of this question you needed