A projectile is thrown with speed 40m/s at angle x from horizontal. It is found that projectile is at same height at 1s and 3s. What is the angle of projection??
I want answer in tan x
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Explanation:
T=2usin¢/g :time of flight is given by this formula
Sin ¢ =gT/u
Now,
Sin¢=2*40/10=1/2
¢=30°
Putting the value of ¢in tan we get,
Tan 30°=1/√3
¢=tan-1(1/√3)
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