Question

a projectile is thrown with speed 60 per second at 60 degree from horizontal it will be at same height at instant ​

Answer 1

Answer:

at time t= 6$\sqrt{3}$ s , the projectile will be at the same height. (taking g=10m/$s^{2}$)

Explanation:

projectile will be at the same height when the vertical component of its velocity is equal in magnitude but opposite in direction, this can be seen using simple kinematics. Or we can say that after covering full horizontal range as a simple projectile at an angle from ground it will be in the same level.

Answer 2

Explanation:

t1 +t2 =6root3

= 10.392

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