Question

A Projectile Is Thrown With Speed U Making Angle Theta With Horizontal Just Close The Two Points At Equal Height At Time T Is Equal To 1 And D Is Equal To 3 Seconds Respectively Calculate Maximum Height Attained By It

Answer 1

Answer:

Maximum Height Attained  = 20 m

Explanation:

Projectile Is Thrown With Speed U Making Angle Theta With Horizontal

Horizontal Velocity = Ucosθ

Vertical Velocity = USinθ

Vertical Distance = S = ut + (1/2)at²

at t = 1

S = USinθ*1 + (1/2)(-g)1² = USinθ*3 + (1/2)(-g)3²

=> 2USinθ = 4g

=> USinθ = 2g

Time taken to reach max height

= (0 - USinθ)/(-g)

= -2g/-g

= 2 sec

H = 2g*2  + (1/2)(-g)2² = 4g - 2g = 2g

= 2 * 10 = 20 m

Maximum Height Attained  = 20 m